a certain quantity of air undergoes a change in state in such a way that 50 kj of heat is transferred to the system . for this change of state the work produced is 40 kj . calculate change in internal energy.assume that process is non flow
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Explanation:
Answer of the sum is 10kj.
∆U=Q - W
∆U =50 - 40KJ
So , ∆U = 10KJ
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