Math, asked by NitishBatham4768, 1 year ago

A certain quantity of petrol is found to be adulterated to the extent of 10%. What proportion of the adulterated petrol should be replaced with pure petrol to take the purity level to 98%?

Answers

Answered by pinquancaro
5

The quantity of petrol is found to be adulterated to the extent of 10%.

Now we need to figure out what proportion of the adulterated petrol should be replaced with pure petrol to take the purity level to 98%.

Since 10% is adulterated that implies 90% of the petrol is pure hence, we can form an equation that will help to answer the proportion to take the purity level to 98%.

x+\frac{9}{10} (100-x)=98

Where 'x' is the percentage of proportion needed to be replaced.

Solve for 'x':

x+\frac{9}{10} (100-x)=98

x+90-\frac{9x}{10} = 98

\frac{10x-9x}{10}=8

x = 80

Therefore, 80% of the adulterated petrol should be replaced with pure petrol to take the purity level to 98%.

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