Chemistry, asked by Alok3042, 1 year ago

A certain reaction is at equilibrium at 82° C and the enthalpy change for this reaction is 21.3 kJ. The value of $\Delta S$ (in JK mol⁻¹) for the reaction is
(a) 55.0
(b) 60.0
(c) 68.5
(d) 120.0

Answers

Answered by Anonymous

$\it\huge\mathfrak\red{answer:-}$ ]

(ethane)-100ml (C2H4 + H2)

= 50ml= 0.05L

P ΔV=1.5*0.05

= 0.075Latm

= 7.5joulesΔU

= ΔH + P ΔV

= -0.31KJ + 7.5J

= -.3025KJ

Answered by naveenjai2004

Answer:

60.0 jk^-1mol_1

Explanation:

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A certain reaction is at equilibrium at 82° C and the enthalpy change for this reaction is 21.3 kJ. The value of (in JK mol⁻¹) for the reaction is (a) 55.0 (b) 60.0 (c) 68.5 (d) 120.0

Answers

A certain reaction is at equilibrium at 82° C and the enthalpy change for this reaction is 21.3 kJ. The value of $\Delta S$ (in JK mol⁻¹) for the reaction is
(a) 55.0
(b) 60.0
(c) 68.5
(d) 120.0