A certain sample of cuprous sulphide is found to have composition cu1.8s because of incorporation of cu2+ ions in the lattice. What is the mole percentage of cu2+ in total copper content in this crystal?
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Answered by
146
Hello buddy,
● Answer- 11.11%
● Explanation-
Molecular formula of pure compound with Cu+ is Cu2S.
Due to impurity of Cu2+ molecular formula becomes Cu1.8S.
Total loss of Copper = 2-1.8 = 0.2 mol
% of Cu2+ in total copper content = 0.2/1.8 × 100 = 11.11 %
Mole percentage of Cu2+ in total copper content is 11.11 % .
Hope this helps you.
Keep asking...
● Answer- 11.11%
● Explanation-
Molecular formula of pure compound with Cu+ is Cu2S.
Due to impurity of Cu2+ molecular formula becomes Cu1.8S.
Total loss of Copper = 2-1.8 = 0.2 mol
% of Cu2+ in total copper content = 0.2/1.8 × 100 = 11.11 %
Mole percentage of Cu2+ in total copper content is 11.11 % .
Hope this helps you.
Keep asking...
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