A certain species of virulent bacteria is being grown in a culture. it is observed that the rate of growth of the bacterial population is proportional to the number present. if there were 4000 bacteria in the initial polulation and the number doubled after the first 30 minutes, how many bacteria will be present after 2 hours?
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64000
after 30min8000
aftr60min 16000
aftr90 min 32000
after 2 hours64000
after 30min8000
aftr60min 16000
aftr90 min 32000
after 2 hours64000
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just first calculate the times mitosis will happen in each cell first
total time = 2 hrs or 120 min
n = no of times mitosis will happen
n = total time / time for one mitosis ;
n= 120/30 = 4
now no of viruses = (initial no of virus )× 2^n
4000× 2^4
4000× 16 = 64000
that was the method for exam now trick wise
just double the initial no for each period
hope it satisfy ..!!!
total time = 2 hrs or 120 min
n = no of times mitosis will happen
n = total time / time for one mitosis ;
n= 120/30 = 4
now no of viruses = (initial no of virus )× 2^n
4000× 2^4
4000× 16 = 64000
that was the method for exam now trick wise
just double the initial no for each period
hope it satisfy ..!!!
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