Question

A certain substance A is mixed with an equimolar quantity of substance B. At the end of an hour, A is 75% reacted. Calculate the time when A is 10% unreacted. (Given: order of reaction is zero)​

Answer 1

According to zero order reaction:

x=kt

75=k×1 and

90=k×t

So t=90/75=1.2 hr

Answer 2

Answer:

Time when A is 10% unreacted is given by $1.2 hrs$

Explanation:

Given: A certain substance A is mixed with an equimolar quantity of substance B. At the end of an hour, A is 75% reacted.

To find: Calculate the time when A is 10% unreacted.

Solution:

According to zero-order reaction:

$x=kt$      ( x = amount of reactant reacted)

$75=k*1$ and

$90=k*t$

So  $t=\frac{90}{75}=1.2 hr$