Question

A certain sum is divided among P, Q and R such that P gets 775 more than one-fourth of the sum, Q gets 512 less than two-fifth of the sum and finally R gets 3510. What is the total sum?
(1) 10,045
(2) 7,550
(3) 8,780
(4) 9,610
(5) None of these

Answer 1

Let the sum be x

P get = 1/4 of x + 775

Q get = 2/5 of x - 512

R = 3510

P + Q + R = sum

x/4 + 775 + 2x/5 - 512 + 3510 = x

x - x/4 - 2x/5 = 3773

(20x - 5x - 8x) / 20 = 3773

7x = 75460

x = 75460/7

x = 10780

so sum was 10780