A certain sum of money amounted to rs. 1020 at 9% in a time in which rs. 720 amounted to rs. 880 at 4%. if the rate of interest is simple, find the sum.
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Here final amount is given 1020 rupees at 9%, and
720 rupees amounted to 880 at 4%
First let us find the time for which 720 amounted to 880 rupees.
P+PNR/100 = 880
720(1+0.04N) = 880
0.04N = 160/720
N = 5.556 years
Now for the amount of 1020/- interest was 9% and time = 5.556 years
TO find P:
P(1+5.556*0.09) = 1020
P (1.50) = 1020
P =680 rs.
Hence the sum = 680 rs.
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