A certain sum of money at compound interest becomes RS 7396 in 2 years and RS7950.70 in 3 years. Find the Rate of Interest.
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Given Amount = 7396 and T = 2 years, Amount = 7950.70 and T = 3 years.
Let the sum be a and the Annual rate of interest be b.
Given Rs.7396 in 2 years.
We know that A = P(1+r/100)^n
7396 = a(1+b/100)^2 ---- (1)
Given Rs.7950.70 in 3 years
A = P(1+r/100)^n
7950.70 = a(1+b/100)^3 ------ (2).
On solving (1) and (2), we get
7950.70/7396= (1+b/100)
1.07500 = 1 + b/100
0.075 = b/100
b = 7.5.
The rate of interest = 7.5%.
Hope this helps!
Let the sum be a and the Annual rate of interest be b.
Given Rs.7396 in 2 years.
We know that A = P(1+r/100)^n
7396 = a(1+b/100)^2 ---- (1)
Given Rs.7950.70 in 3 years
A = P(1+r/100)^n
7950.70 = a(1+b/100)^3 ------ (2).
On solving (1) and (2), we get
7950.70/7396= (1+b/100)
1.07500 = 1 + b/100
0.075 = b/100
b = 7.5.
The rate of interest = 7.5%.
Hope this helps!
Satyam2772:
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