A certain sum of money doubles itself at a simple interest in 8 years. In how many years it will be 3 times at the same rate?
Answers
Answered by
7
let the sum of money be x
amount =2x
simple interest =A-P
=2x-x
= x
time =8yrs
rate =si*100 /p*t
= x*100/x*8
= 12.5 %
p= x
a= 3x
si = A-P
= 3x -x
= 2x
rate = 12.5 %
t = si * 100/p*r
t = 2x*100/x*12.5
t= 16
amount =2x
simple interest =A-P
=2x-x
= x
time =8yrs
rate =si*100 /p*t
= x*100/x*8
= 12.5 %
p= x
a= 3x
si = A-P
= 3x -x
= 2x
rate = 12.5 %
t = si * 100/p*r
t = 2x*100/x*12.5
t= 16
sahi14:
easy sum
Answered by
3
Answer:
Step-by-step explanation:
let the sum of money be x
amount =2x
simple interest =A-P
=2x-x
= x
time =8yrs
rate =si*100 /p*t
= x*100/x*8
= 12.5 %
p= x
a= 3x
si = A-P
= 3x -x
= 2x
rate = 12.5 %
t = si * 100/p*r
t = 2x*100/x*12.5
t= 16
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