Math, asked by ashkate, 4 months ago

a certain sum of money doubles itself in 8 years . how much time will it take to triple itself in the same rate.

Answers

Answered by kangule
2

Answer:

(SI in case first)/(SI in case second) = (Time in case first)/(Time in case second)

SI1/SI2 = T1/T2

1/3 = 8/T2

T2 = 24 years

Step-by-step explanation:

SI = P*R*T/100

When principal amount P and rate of interest R is same or constant in both cases then simple interest or the ratio of simple interest will be directly proportional to the time or ratio of time

SI1/SI2 = T1/T2

Ratio of Simple interest in both case will be 1:3

In first case the simple interest will be one time of principal amount or initial value because the initial value is becoming double of itself

But in second case the simple interest will be 3 times of principal amount or initial value because the initial value is becoming 4 times of itself

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