A certain sum of money doubles itself in 8years. In how many years will it get 5 times
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Answers
Answer:
A certain sum of money doubles itself in 8 years. In how much time will it become 4 times of itself at the same rate of interest?
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There are many different ways to solve this problem but I choose this one
(SI in case first)/(SI in case second) = (Time in case first)/(Time in case second)
SI1/SI2 = T1/T2
1/3 = 8/T2
T2 = 24 years
Explanation:-
SI = P*R*T/100
When principal amount P and rate of interest R is same or constant in both cases then simple interest or the ratio of simple interest will be directly proportional to the time or ratio of time
SI1/SI2 = T1/T2
Ratio of Simple interest in both case will be 1:3
In first case the simple interest will be one time of principal amount or initial value because the initial value is becoming double of itself
But in second case the simple interest will be 3 times of principal amount or initial value because the initial value is becoming 4 times of itself
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Let the principle be 100.
Then amount will be 200.
Interest= 100
Time = 8 yrs
R=?
I=PRT/100
100=100*R*8/100
100*100/100*8=R
100/8=R
NOW SUM SHOULD BE 4 TIMES MEANS 400
MEANS INTREST ON 100 IS 300.
I=PRT/100
300=100*100/8*T/100
300*8/100=T
follow the method and try to solve
Step-by-step explanation:
the answer is 20 times once watch all pics
