Question

A certain volume of gas was confined in a rigid container. If the pressure of the gas sample in the container was doubled what happened to the temperature?

Answer 1

Answer:

The final temperature of the gas will also get doubled.

Explanation:

Initial pressure of the gas = P

Final pressure of the P'= 2P

Initial temperature of the gas = T

Final Temperature of the gas = T'

Applying Gay Lussac's law:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\frac{P}{T}=\frac{2P}{T'}$

T' = 2T

The final temperature of the gas will also get doubled.