At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?
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Assume the gas to be ideal,
n= 19.4/16+16+16 = 19.4/48.
P= 1820 * 133.3 Pascal.
V in L.
R= 8.314
Find T.
It will be in K so subtract 273 from it to get the temperature in °C.
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