Chemistry, asked by rajlanjhi63151, 1 year ago

At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?


Anonymous: ___k off

Answers

Answered by aryanm468
0

Assume the gas to be ideal,

n= 19.4/16+16+16 = 19.4/48.

P= 1820 * 133.3 Pascal.

V in L.

R= 8.314

Find T.

It will be in K so subtract 273 from it to get the temperature in °C.

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