Question

a certain wire has a radius R another wire of same resistance,has half the length and half the diameter of the first wire.the resistance of second wire is


please answer this question with step by step explanation and don't give any irrelevant answers ​

Answer 1

Explanation:

R1 = L/D² where L is length And D is the diameter of the wire.

in the second case, according to question.

R2 = (L/2)/(D/2)²

R2 = L/2 / D²/4

R2= (L/2) × 4/D²

R2 = 2(L/D²)

R2 = 2 R1

hope the question is answered.