Question

(a) CH2CH=CH2

is treated with (A) HBr and (B) aqueous KOH​

Answer 1

Answer:

First reaction is as follows:

CH2=CH2+HBr→CH2Br−CH3

In presence of alc. KOH, following reaction takes place:

CH3−CH2Br+KOH→CH2=CH2+KBr

In this process, alc. KOH is used for dehydrohalogenation.