Question

A chain of mass m and length L is held at rest on
smooth horizontal surface such that a part I of the
chain is hanging vertically from the table. If the
chain is let go, what is its speed as its end just
leaves the horizontal surface?​

Answer 1

Answer:

Explanation:    i hope it's better for you

Answer 2

Explanation:

mass of length L is M

mass of length 1m is M/L

mass of length l is m= M/L (l)

reference from the table

C.O.M of l length is l/2

P.E initial = mgl/2

= Ml²g/2

P.E final = MgL/2

K.E initial = 0

K.E final = MV²/2

by conservation of energy

we get

V = √g(L - l²/L)

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