Math, asked by Anonymous, 4 months ago

A challenge For all Aryabhatta's and Moderators .

Ans - 7 , -17/2 .

Don't Spam . Did it on your own intelligence​

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Answers

Answered by mathdude500
4

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\huge {AηsωeR} 

\bf \: \frac{2}{2a + 1} \int_0^1x^adx =  \frac{1}{60}

\bf \: \frac{2}{2a + 1} [ \frac{ {x}^{a + 1} }{a + 1}  ]_ {0}^{1}  =  \frac{1}{60}

\bf \: \frac{2}{2a + 1}  \times  \frac{1}{a + 1}  =  \frac{1}{60}

\bf\implies \:(2a + 1)(a + 1) = 120

\bf \:2 {a}^{2}  + 3a + 1 = 120

\bf \:  ⟼ 2 {a}^{2}  + 3a - 119 = 0

\bf \:a =  \dfrac{ - 3 \: ± \:  \sqrt{9 + 952} }{4}

\bf \:a = \dfrac{ - 3 \: ± \: 31}{4}

\bf \:a  = \dfrac{ - 3 + 31}{4}  \: and \: \dfrac{ - 3 - 31}{4}

\bf\implies \:a =  7 \: and \:  - \dfrac{17}{2}

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Anonymous: Fir bhi maths Aryabhatta nhi ban paye bhai . Kyo
mathdude500: Don't know about this
mathdude500: I have very few thanks might be
mathdude500: Very few followers
Anonymous: Tennetiraj86 ke 12800 + answer hai maths me Fir bhi vo genius hi hai Smajh hi nhi aata
mathdude500: Ohhh
mathdude500: Really good
Anonymous: jha tak mujhe pata hai ki tennetiraj86 se jyada kisi moderator ke maths me answer nhi hai .
Anonymous: 200 answer vale math Aryabhatta ban jate hai par jinke pas kabiliyat hai vo nhi kar pate . Bhagwan ne ajib chij banayi
mathdude500: Truly said
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