Question

A challenge for u all...

When a two digit no is divided by sum of its digits ,the quotient is 4.
And when it is divided by difference of its digits, the quotient is 12.

Find the number.

May look easy but there will several answer. But they have something in common . Those will write the first common thing will get BRAINLIEST and 5 ​

Answer 1

Answer:

Let the digit at tens place be x and the digit at units place be y.

Therefore the no. is— (10x+y ) ——————————-as x is at tens place.

(10x+y)/(x+y) =4

10x+y=4(x+y)

10x+y=4x+4y

6x=3y

(2x=y )——————————————————————————————- 1

Now the digits are interchanged.

Therefore the new no is —( 10y+x)

As the new no is 6 less than twice the original no.—

Therefore,

10y+x=2(10x+y)-6

10y+x+6=20x+2y

10y-2y+6=20x-x

8y+6=19x

(8y+6)/19=x

As we have got the value of x,lets substitute it in equation 1

Therefore,

2(8y+6)/19=y

16y+12=19y

12=19y-16y

12=3y

y=12/3=4

y=4

Substituting the value of y in equation 1

Therefore,

2x=4

x=4/2=2

x=2

y=4

Therefore the no. is

10x+y=10(2)+4=20+4=24

Therefore the no. is 24

Answer 2

Answer:

hi your lD

please........