Question

A chamber of constant volume contains Hydrogen gas. When the chamber is immersed in a bath of melting ice 100°C. The pressure of the gas is 1.06×10^2 k pascal. What pressure will be indicated when the chamber is brought to 100°C

Answer 1

The pressure indicated is P =  1093.04 torr

Explanation:

We are given that:

Pressure of the gas =  1.06×10^2 k Pascal

PV = nRT

Where

• P = pressure
• V = volume
• r = gas constant
• T = Absolute temperature

C = k - 273

K = C + 273

100°C --> 100 + 373 = 373 K

800 x V = n x R x 273    ----(1)

P x V = n x R x T  ---(2)

800 / P = 273 / 373

P =  1093.04 torr

Thus the pressure indicated is P =  1093.04 torr

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Answer 2

Given:

Pressure, P = 1.06×10² k pascal

Temperature = 100°C

To Find:

Indicated pressure = ?

Solution:

As we know,

⇒  $PV=nRT$

and,

$C=k-273$

$K=C+273$

Now,

⇒  $100^{\circ}\rightarrow 100+373=373 \ K$

⇒  $800\times V=n\times R\times 273$ ...(equation 1)

⇒ $P\times V =n\times R\times T$ ...(equation 2)

From "equation 1" and "equation 2", we get

⇒  $\frac{800}{P}=\frac{273}{373}$

On applying cross-multiplication, we get

⇒  $273P=800\times 373$

⇒  $273P=298400$

⇒  $P=\frac{298400}{273}$

⇒  $P=1093.04 \ torr$

So that the pressure will be "1093.04 torr".