Question

plz answer fast ....... irrelevant answers will be reported and if ur answer is right I will follow u and like ur answers and mark u as brainilist.....​

Answer 1

first we have to find the syms of zeroes.........as....

==> $\alpha + \beta = 4-12/a$==> - 12/1

==>$\alpha + \beta = -8/a$ -8/1

==> $\alpha *\beta = -48/a$  -48/1

required equation is......

==> $x^{2} -(sum of zeroes)x + product of zeroes$

==>$x^{2} + 12x - 48 =0$

hope u got ur answer......

Answer 2

first we have to find the syms of zeroes.........as....

==> \alpha + \beta = 4-12/aα+β=4−12/a ==> - 12/1

==>\alpha + \beta = -8/aα+β=−8/a -8/1

==> \alpha *\beta = -48/aα∗β=−48/a -48/1

required equation is......

==> x^{2} -(sum of zeroes)x + product of zeroesx

2

−(sumofzeroes)x+productofzeroes

==>x^{2} + 12x - 48 =0x

2

+12x−48=0

hope it's helps u