A change 3 coulomb is moving velocity →v=(4ˆi+3ˆj)ms−1 in a magnetic field →B=(4ˆi+3ˆj)wbm−2Find the force acting on the charge
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The Force on a charge in a Magnetic Field is given by,
F = q(v × B)
here q= 3, B = 4i + 3j, v=4i + 3j
Observe B=v, so
v × B =0
F= 3 x 0 = 0
So, No force acts on the charge
F = q(v × B)
here q= 3, B = 4i + 3j, v=4i + 3j
Observe B=v, so
v × B =0
F= 3 x 0 = 0
So, No force acts on the charge
Answered by
2
Answer: Zero
Explanation: F = q( v x B) = 3[ (4i + 3j) x (4i = 3j) ] = 3[0] = 0
∵Cross product of two vector is zero.
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