if cos 9 alpha is equal to sin alpha and 9alpha less than 90degrees
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Alpha is 9 and 9alpha is 81.
The solution is
Cosθ=Sin(90-θ)
Cos9alpha=son alpha
But cos 9alpha=son(90-9alpha)
Therefore
Alpha =90-9alpha
Thus
10alpha=90
So
Alpha =90/10
Alpha =9
And 9alpha =81
Hope it helps
The solution is
Cosθ=Sin(90-θ)
Cos9alpha=son alpha
But cos 9alpha=son(90-9alpha)
Therefore
Alpha =90-9alpha
Thus
10alpha=90
So
Alpha =90/10
Alpha =9
And 9alpha =81
Hope it helps
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