Physics, asked by yashsingh2132, 11 months ago

A charge of -100e is kept at a point and a point charge of +10e is moved.
once around it in a circular path of radius 'r'. The work done is
(a) -1000e^2/r^2
(b) 90e^2/r^2

(c) 9 x 10^9x 100e
(d) zero​

Answers

Answered by aristocles
0

Answer:

The work done is ZERO

Explanation:

When one charge -100e is fixed at a point and another charge +e is moving around it then we know that potential due to a point charge is given as

V = \frac{kQ}{r}

so potential due to a point charge at a distance "r" from it is fixed and it will not change

so if another charge is moving around the fixed charge in constant radius then it will have

W = q(\Delta V)

where we have

\Delta V = 0

so we have

W = 0

#Learn

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