Science, asked by aanubhavverma96, 11 months ago

A charge of 200 coloumb flow through a bulb of resistance 20ohm for 25 sec find the potential difference across a bulb​

Answers

Answered by stevesman201
1

Explanation:

Q=200 coulombs

R=20 ohms

t=25 secs

I=Q/T=200/25=8 ampere

potential difference=IR

=8×20=160 volt

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