A charge of √2C is placed at the top of your school building and another equal
charge at the top of your house. Take the separation between the two charges to be 2
km. How much force is exerted by the charges on each other?
Answers
Answered by
0
Explanation:
Using Coulumb's law.
F = k q₁q₂/r² k(for air)= 9*10⁹
F = k (√2 * √2)/(2 km)²
= k * 2/(2000 m)²
= 9 * 10⁹ * 2/4*10⁶ N
= 9 * 10⁽⁹⁻⁶⁾ /2
= 4.5 * 10³ N
Answered by
0
Answer:
4.5 kN
Explanation:
Both charges are equal
therefore, Q1 =Q2= √2
distance between the charges,
r = 2km
= 2000m { we can write it as 2x10^3 m }
k= 9x10^9 N
Now, by coulomb's law
F= k Q1 Q2/r^2
Put values
F= 9x10^9x√2x√2 / (2x10^3)^2
F= 9x10^9x2 / 4 x 10^6
F= 9x10^(9-6) / 2
F= 9x10^3 / 2
F= 4.5x10^3 N
Therefore the answer is 4.5x10^3 N or 4.5 kN
Thank you, Hope you understood this
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