helium gas is filled in a two indicator bottles A and B the mass of the gas in the two bottles is 10 gm and 40 gm respectively .If the speed of sound is the same in both bottles , what conclusion will you draw?
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Mass of helium in bottle A is 10g = M1
Mass of helium in bottle B is 40g=M2
Speed of sound in bottle A is equal to speed of sound in bottle B
V1 =V2
Therefore , root T1 / root M1 - root T2 / root M2
Therefore, T1 / M1 - T2 / M2
Therefore , T1 / 10 - T2 / 40 ( 4 T1 =T2 )
Temperature of bottle B is 4 times that of Bottle A.
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