A charge of 2C moves between two plates maintained at a potential difference of 1V. What ia the energy acquired by the charge ?
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Explanation:
As per the given conditionsQ = 2 C, Potential difference V = 1V.
Putting the known values in equation (i),
Energy acquired by the charge,
W = QV
= 2 x 1
= 2 Joule
Energy acquired by the charge= 2 Joule
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Answer: 2 Joule.
Explanation:
- Given, Charge(Q)=2 Coulombs and potential difference (V)=1 Volt.
- We know that to calculate the work done W by a charge Q separated by a potential difference V is given by
W= Q*V
⇒W= 2*1
∴ W= 2 Joule
- Hence, the work done by a charge of 2 Coulombs separated by a potential difference of 1 Volt is 2 Joule.
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