A charge of 2nc is distributed in a sphere of radius 1cm find surface density
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GIVEN;q=2nC=2×10^-9C , r=1cm=1×10^-2m=10^-2m
TO FIND; surface density=?
SOLUTION;
S.D=q/4πr^2
S.D=2×10^-9 / 4×3.14×(10^-2)^2
S.D=2×10^-9 / 4×3.14×10^-4
S.D=2×10^-9 / 12.55×10^-4
S.D=0.1592×10^-9×10^4
S.D=0.1592×10^-5
S.D=1.592×10^-6Cm^-2
TO FIND; surface density=?
SOLUTION;
S.D=q/4πr^2
S.D=2×10^-9 / 4×3.14×(10^-2)^2
S.D=2×10^-9 / 4×3.14×10^-4
S.D=2×10^-9 / 12.55×10^-4
S.D=0.1592×10^-9×10^4
S.D=0.1592×10^-5
S.D=1.592×10^-6Cm^-2
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