a number consists of two digits whose sum is 9. if 9 is subtracted from the number its digits are interchanged. findthe number
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Let the two digit number has X in ten's place and Y in unit place.
=> Number = 10X + Y
Given,
X + Y = 9 ------------(1)
On reversing the order of the digits , the number formed = 10Y + X.
Also given, 10X + Y - 9 = 10Y + X
=> 10X - X + Y - 10Y = 9
=> 9X - 9Y = 9
=> 9 ( X - Y ) = 9
=> X - Y = 1 ----------(2)
From (1) , we get
X + Y = 9
X = ( 9 - Y ) ----------(3)
Putting X = ( 9 - Y ) in equation (2),
X - Y = 1
9-Y - Y = 1
-2Y = -8
Y = 4.
Putting Y = 4 in equation (3),
X = ( 9 - Y ) = 9-4
X = 5.
Therefore , Required number = 10X + Y = 10 × 5 + 5 = 54.
=> Number = 10X + Y
Given,
X + Y = 9 ------------(1)
On reversing the order of the digits , the number formed = 10Y + X.
Also given, 10X + Y - 9 = 10Y + X
=> 10X - X + Y - 10Y = 9
=> 9X - 9Y = 9
=> 9 ( X - Y ) = 9
=> X - Y = 1 ----------(2)
From (1) , we get
X + Y = 9
X = ( 9 - Y ) ----------(3)
Putting X = ( 9 - Y ) in equation (2),
X - Y = 1
9-Y - Y = 1
-2Y = -8
Y = 4.
Putting Y = 4 in equation (3),
X = ( 9 - Y ) = 9-4
X = 5.
Therefore , Required number = 10X + Y = 10 × 5 + 5 = 54.
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