Question

A charge of 5 C is moved between two points in an electric field and 20 J of work was done to do so. Calculate the potential between the two points.​

Answer 1

$\bold{Question:-}$

A charge of 5 is moved between two points in an electric field and 20 J of work was done to do so. Calculate the potential between the two points.

$\bold{Given:-}$

charge to be moved in an electric field,

= 5C = q,

work done=20J.

$\bold{To\:find:-}$

potential difference b/w 2 point.

$\bold{Answer:-}$

We know that,

Work = ( charge × potential difference )

b/w 2 point.

so, potential difference b//w 2 point.

$v = \frac{work \: done}{charge}$

$= \frac{20}{5} = 4v$

Ans:- potential difference between 2 points is 4v.

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Answer 2

Answer:

$\huge\underline\bold {Solution :}$

Given,

charge, q = 5 C

Work done, w = 20 J

Potential energy = Work done/charge

=> V = w/q

= 20J/5C = 4 V

Therefore potential energy is 4 V.