Physics, asked by vishwak36, 6 months ago

A charge of 5 coulombs is moved into an electric field from infinity, when the work
done at point A is 20 J and at point B is 32 J. Calculate the potential difference
between points A and B.​

Answers

Answered by hitakshi22022005
1

Answer:

V=W/Q

Potential difference at point A is 20/5=4 V

Potential difference at point B is 32/5=6.4 V

Hence the difference of potential between point A and B is 6.4-4=2.4 V

:)

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