A charge of 5 x10-9 c is attracted by a charge of -3x10-7 with a force of 0.135 n
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Question :
A charge of 5 × 10-⁹ C is attracted by a charge of - 3 × 10-⁷C with a force that 0.135 N , find the distance between them.
Given :
- Charge (Q) = 5 × 10-⁹C.
- Charge (q) = -3 × 10-⁷C.
- Force (F) = 0.135 N.
To find :
Distance between the two charges.
Solution :
We know the formula for Force between two charges i.e,
Where :
- F = Force field .
- Q = Charge on the body.
- q = Charge on the body.
- r = Distance between the two charges.
- 1/4πε = E = Electric field strength.
Now using the above formula and substituting the values in it, we get :
Hence the distance between the two charges is 0.1 m.
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