Question

A charge of 5000 C flows through an electric circuit in 2.5 hrs. Calculate the magnitude of current flowing through the circuit

Answer 1

Answer:

0.55 A

Explanation:

GIVEN-:

current = 5000 c

Time = 2.5 hr

= 2.5 × 3600 sec

= 9000 sec

Now,

Current = Charge / Time

I = 5000/9000

I= o.55A

Hope this will help you...

Thank you

Answer 2

Answer:

0.55 Amp

Explanation:

Given:

charge [q ] = 5000 C

time [t] = 2.5 hrs = 9000 seconds

To Find:

magnitude of current = ?

Solution:

Current = charge/time -----> q/t

current = 5000/9000

current = 5/9

current = 0.55 Amp

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