Question

A charge of 5c is placed at the centre of a spherical gaussian surface of radius 5 cm the electric flux through the surface is

Answer 1

Hope you got an answer

Answer 2

Given:

• 5C charge is placed at centre of Gaussian surface of radius 5cm.

To find:

Flux through surface ?

Calculation:

Let the flux be $\phi$

$\phi = E \times s$

• E is field intensity and s is surface area.

$\implies \phi = \dfrac{kq}{ {r}^{2} } \times 4\pi {r}^{2}$

$\implies \phi = \dfrac{q}{4 \pi\epsilon_{0}} \times 4\pi$

$\implies \phi = \dfrac{q}{\epsilon_{0}}$

• Value of $\epsilon_{0}$ is 8.85 × 10^(-12)

$\implies \phi = \dfrac{5}{8.85 \times {10}^{ - 12} }$

$\implies \phi = 0.56 \times {10}^{ 12} \: N {m}^{2} /C$

So, flux is 0.56 × 10¹² Nm²/C