A charge of 6 C is moved between two points P and Q having, potential 10V and 5V respectively.find the amount of work done.
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Answer:
Given,
Charge, q=6C
Potential difference, v=(10V-5V) =5V
Work done=W=?
Explanation:
As we know that:
V=W/q
5V=W/6C
W=5V*6C
W=30J
Hence ,the amount of work done is 30J.
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