prove 2√2 divided by 5 is irrational
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Step-by-step explanation:
Let (3√2)/5 be a rational number in the form p/q. Here, 5p/3q is a rational number because it is expressed in form of p/q. This means that √2 rational. ... Therefore, (3√2)/5 is an irrational number
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Step-by-step explanation:
Let, (2√2)/5 be a rational number.
Then, (2√2)/5 = a/b [ where a and b are natural numbers, a and b both are ≠ 0]
(2√2)/5 = a/b
2√2 = 5a/b
√2 = 5a/2b
since a, b, 5and 2 are ratonal so 5a/2b is rational
so, √2 is rational
But it contradict the fact that √2 is an irrational number
so, our assumption is wrong
Hence, (2√2)/5 is an irrational number
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