Question

A charge of 6 c is moved between two points P and Q having, potential 10 V and 5V respectively. Find the work done

Answer 1

Answer:charge = 6c

Potential difference = 10v- 5 v= 5v

W=. V × Q = 6 × 5 = 30 J

Hope it will help.....

Explanation:

Answer 2

Given:

The magnitude of the charge = 6C

The potential of point P = 10V

The potential of point Q = 5V

To Find:

The work done

Solution:

The work done is -30 J.

To move a charge across two points that have some potential difference between them, external work needs to be done.

This work is directly proportional to the magnitude of the charge and the potential difference between the two points.

Mathematically,

W = q.ΔV

In the question, the charge travels from P to Q

⇒ ΔV = Final potential - Initial potential

= Vq - Vp

= 5 - 10

= -5V

The work done = 6 X (-5) J

= -30J

(The work done is negative because we are moving a positive charge from higher potential to lower i.e. opposite the electric field.)