Question

A charge particle after being accelerated through a potential difference V

enters in a uniform magnetic field and moves in a circle of radius r. If V is

doubled, the radius of the circle will become

(a) 2r

(b) root 2r

(c) 4r

(d) r/ root2​

opt d is the answer right? ( r=mv/qB, v=f x lambda lambda proprtional to 1/rootV so ..r proprtional to 1/root V?

Answer 1

Answer:

d) r/root2

Explanation:

r=mv/qB,v=fx, lamda propptional to 1/root v