Physics, asked by garvitjain311, 8 months ago

A charge particle of mass 10 gm & charge 1
mili coulomb is projected with velocity 30
m/sec perpendicular to uniform electric field
of strength 100 V/m. Its speed after 4
second will be:

1)30 m/sec
2)
40 m/sec
3)
50 m/sec
4) 502 m/sec​

Answers

Answered by simarahluwaliasimar
0

Answer: 30 m/s

Concept: Motion of particle in electric field

Given:

a)Mass of particle (m)= 10gm

b) Charge of particle (Q)= 1 mC

c) Velocity of particle (V)= 30 m/s

d) Strength of uniform electric field = 100 V/m

To Find: The Speed of the particle after 4 seconds.

Step-by-step explanation:

A charge's locus will be an equipotential surface if it is moved so that each of its positions always remains perpendicular to the direction of the electric field. Moving the charge between any two points on this equipotential surface will not involve any work. This is because every point on this surface will have a constant electric potential energy from the charge. Thus, no work will be done and there won't be any change in a charged particle's potential energy if it is shifted so that its location always remains perpendicular to an electric field. Also, the speed of the particle will remain same when a particle is moved to the uniform electric field.

Thus, the speed of the particle after 4 seconds will be 30 m/s.

Project Code: #SPJ2

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