Question

a refrigerator tajes heat from water at 0°c and transfer it to room at 27°c . if 100kg of water is coverted in ice at 0°c then calculate the work done.

$(latent \: heat \: of \: ice \: is \: 3.4 \times {1}^{5} j \: kg)$
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Answer 1

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Answer 2

$\huge{\underline{\underline{\mathbf{Answer:-}}}}$

$3.36\times {10}^{6} j$

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$\huge{\underline{\underline{\mathbf{Explanation:-}}}}$

Coefficient of performance (COP) =  

$\large\boxed{ \frac{ t_{2}}{ t_{1} - t_{2}} }$

✍$\large\bold{\frac{273}{300 - 273}}$

✍$\large\bold{\frac{273}{27}}$

and,

$\large\bold{w = \frac{ q_{2} }{cop}}$  =  $\large\bold{\frac{ml}{cop}}$

✍$\large\bold{ \frac{100 \times 3.4 \times {10}^{5} }{ \frac{273}{27} } }$

✍$\large\bold{ \frac{100 \times 3.4 \times {10}^{5} \times 27}{273} }$

$\large\bold{3.36\times {10}^{6} j}$

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