A charge q is in a sphere and the electric flux leaving out is
Answers
Answer:
If you dont know Gauss’ law, you can try to see it intuitively. The flux out of a surface is proportional to the number of electric field lines passing through the surface. The surface in question has two charges, +q and - q. They both have same magnitude. The positive charge will act as a source, with field lines coming out of it. The negative charge is a sink, and field lines will fall into it. Since the charges are of equal strength, the number of charges coming out of the source will be equal to the number of charges falling into the sink, making the net flux out of the surface 0.
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Explanation:
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Answer:
If you dont know Gauss’ law, you can try to see it intuitively. The flux out of a surface is proportional to the number of electric field lines passing through the surface. The surface in question has two charges, +q and - q. They both have same magnitude. The positive charge will act as a source, with field lines coming out of it. The negative charge is a sink, and field lines will fall into it. Since the charges are of equal strength, the number of charges coming out of the source will be equal to the number of charges falling into the sink, making the net flux out of the surface 0.