Physics, asked by Kiriti110824, 1 month ago

A charge q is placed at point P as shown inside a spherical conducting shell of radius R and having charge Q. The electric potential at surface of shell is​

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Answered by prachikalantri
0

The electric potential (also called the electric field potential, potential drop, the electrostatic potential) is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field. More precisely, it is the energy per unit charge for a test charge that is so small that the disturbance of the field under consideration is negligible. Furthermore, the motion across the field is supposed to proceed with negligible acceleration, so as to avoid the test charge acquiring kinetic energy or producing radiation. By definition, the electric potential at the reference point is zero units. Typically, the reference point is earth or a point at infinity, although any point can be used.

The surface area of a solid object is a measure of the total area that the surface of the object occupies.

Electric potential due to the point of charge =k\frac{q}{R}

Electric potential due to the inner surface of the shell =-\frac{kq}{2R}

and electric potential due to the outer surface of the shell =\frac{kq}{3R}

V=k\frac{q}{R}-\frac{kq}{2R}  +\frac{kq}{R}[1-\frac{1}{2}-\frac{1}{3}  ]

=\frac{k5q}{6R}

#SPJ2

Answered by rajagrewal768
0

Answer:

Electrode potential V = 5kq/r

Explanation:

We have to find electric potential at point V which lies inside the shell due to charge on the surface of the shell q and the charge inside the shell . Hence the total potential will be the summation of the two electric potentials.

#SPJ2

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