Question

a charge q is uniformly distributed over a rod of length l .consider a hypothetical cube of edge l with the centre of the cube at one end of the rod.find the minimum possible flux of the electric field through the entire surface of the cube​

Answer 1

The flux of the electric field through the entire surface of the cube​ is Flux =(Q/2(ε0).

Explanation:

Given data:

• Length of the rod = edge of cube = l
• Portion of rod inside the cube = l/2

Total charge = Q

Linear charge density = (Q / l(ε0)) of rod

We know that:

Flux = charged enclosed in the  rod inside the cube

Flux = l / 2 × (Q / l(ε0))

Flux =(Q/2(ε0)

Thus the flux of the electric field through the entire surface of the cube​ is Flux =(Q/2(ε0).

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