Calculate mass of oxygen required to burn 14 g and C2H4 completely
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Answered by
14
C2H4 burns as follows,
C2H4 + 3O2---> 2CO2+ 2H2O
To burn 26 g of C2H4, 96 g of oxygen is reqd.
∴ To burn 14 g of C2H4, 96/26 x 14= 51.7 g of oxygen is reqd.
Therefore, to burn 14 g of C2H4 completely, 51.7 g of O2 is reqd. C2H4 is called Ethene.
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Answered by
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Answer:
C2H4 burns as follows,
C2H4 + 3O2 ⇄ 2CO2+ 2H2O
To burn 26 g of C2H4, 96 g of oxygen is required
∴ To burn 14 g of C2H4, 96/26 x 14= 51.7 g of oxygen is required
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