Question

A charge ‘q' moving in a straight line is accelerated by a potential difference ‘v'. it enters a uniform magnetic field ‘b' perpendicular to its path. deduce in terms of v an expression for the radius of the circular path in which it travels

Answer 1

This is what happens when a charge and mass moves perpendicular in the direction of a magnetic field: mv/r2 = BQv, or 2E = BQr, or 2E = BQ(rW)r = BQr2(2πV).

Then the frequency of the rotation becomes, V = E / BQr2π and r = √(BQπV / E)