A charge Q the electric flux passed through all the six faces of the cube is :
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Let the charge is located at origin and the corner of the cube also at origin.
Using Gauss's law and symmetrical argument:
now if we place 7 more cubes around original cube. Each face of this new cube contains 4 faces of original.
The new big cube has 6 faces placed symmetrically around origin, total= 24 faces.
now the total flux according to Gauss's law is q/ε₀.
therefore, flux through each face is q/24 ε₀.
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αnѕwєr⤵
- Let the charge is located at origin and the corner of the cube also at origin.
- Using Gauss's law and symmetrical argument:
- now if we place 7 more cubes around original cube. Each face of this new cube contains 4 faces of original.
- The new big cube has 6 faces placed symmetrically around origin, total= 24 faces.
- now the total flux according to Gauss's law is q/ε₀.
- therefore, flux through each face is q/24 ε₀.
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