Question

At 27ºC latent heat of fusion of a compound is 2930 J/mol. Entropy change is :

Answer 1

here is your answer hope it helps

Answer 2

Answer:

The change in entropy is 9.77 J/mol.K

Explanation:

The change in entropy can be calculated as

$\Delta S=\frac{q_{rev} }{T}$

Here, $q_{rev}$ is the reverse of the heat and T is the temperature in kelvin.

Given $q_{rev}=2930J/mol$  and $T=27 \ ^0C= 27 +273 = 300 K$

substitute the given values, we get

$\Delta S=\frac{2930}{300}$

$\Delta S=9.77\ J/mol K$

Thus, the change in entropy is 9.77 J/mol K.

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