Question

A charged particle (charge q) is moving in a circle of radius r with uniform speed v. The associated magnetic momentu µ is given by

Answer 1

magnetic moment = qvr/2

Answer 2

The revolving charged particle will be equivalent to the current , so

I= q/T,

q- charge

T- time period of revolution

T = 2π/w [w = v/r, r is the radius of the circle and v is the velocity of the charge .]

T = 2πr/v

Therefore ,

I = qv/2πr

The magnetic moment will be equal to the product of the current flowing and the area -

μ = I ×A,

I - current

A - area of the circle

A=π r^2 , I = qv/2πr

μ=(qv/2πr)×πr^2

= qvr/2