Question

a charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x
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Answer 1

Given : A charged particle has acceleration a vector = 2 i^ + x j^ in a magnetic field B Vector = -3 i^ +2 j^ -4 k^.

To find : magnetic force acting on the particle is perpendicular on magnetic field.

so, acceleration is also perpendicular on magnetic field.

means, dot product of acceleration and magnetic field must be zero.

i.e., a.B = 0

⇒(2 i + x j).(-3 i + 2 j - 4 k) = 0

⇒(2) × (-3) + x × 2 + 0 = 0

⇒-6 + 2x = 0

⇒x = 3

Therefore the value of x = 3.

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